怎样求y=(x²-5x+6)/(x²+x-6)的值域
怎样求y=(x²-5x+6)/(x²+x-6)的值域
数学人气:450 ℃时间:2020-05-21 14:58:38
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y=(x²-5x+6)/(x²+x-6)因式分解,得到y=(x-2)(x-3)/(x+3)(x-2) 其中x不等于2或-3分式上下同消去(x-2)y=(x-3)/(x+3)=(x+3-6)/(x+3)=1-6/(x+3)因为x不等于2,所以y不等于1-6/5=-1/5又因为6/(x+3)不等于0,所以y...
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