y^2=8x的焦点(2,0)
双曲线x^2/a^2-y^2/b^2=1的渐近线
x^2/a^2-y^2/b^2=0
y=±b/ax
运用点到直线的距离公式得
|2b/a|/√[1+(b/a)^2=√2
2b/√(a^2+b^2)=√2
平方得
4b^2=2a^2+2b^2
a=b
所以双曲线的离心率为√2
若抛物线y^2=8x的焦点到双曲线x^2/a^2-y^2/b^2=1(a>0,b>0)一条渐近线的距离根号2,则双曲线的离心率为
若抛物线y^2=8x的焦点到双曲线x^2/a^2-y^2/b^2=1(a>0,b>0)一条渐近线的距离根号2,则双曲线的离心率为
数学人气:291 ℃时间:2020-05-17 15:19:37
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