设f(x)=16x/x²+8(x>0),(1)求f(x)的最大值(2)证明:对任意实数b恒有f(x)<b²-3b+21/4
设f(x)=16x/x²+8(x>0),(1)求f(x)的最大值(2)证明:对任意实数b恒有f(x)<b²-3b+21/4
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数学人气:350 ℃时间:2019-11-01 11:34:07
优质解答
(1) f(x)=16x/(x^2+8)=16/(x+8/x)=3>2√2>=f(x)
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