过点M[2,0]且被圆X^2+[y+1]^2=9截得的线段长为2倍根号下5的直线方程为
过点M[2,0]且被圆X^2+[y+1]^2=9截得的线段长为2倍根号下5的直线方程为
数学人气:268 ℃时间:2020-03-28 01:56:54
优质解答
这种题目肯定有2解首先把图画出由题得圆心到该直线的距离为2(由勾股定理得)1.k不存在时该直线为x=2该方程成立2.k存在时设该直线方程为y=kx-2k(该直线过M点)∴|1-2k|/根号下(1+k^2)=2解得k=-3/4 ∴y=-3/4x+2/3综...
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