a2-2ab-b2/ a2-3ab+b2?
应该是(a²-2ab-b²)/ (a²-3ab+b²)吧?
已知a/b=1/3,b=3a,
则(a²-2ab-b²)/ (a²-3ab+b²)
=[a²-2a(3a)-(3a)²]/ [a²-3a(3a)+(3a)²]
=[a²-6a²-9a²]/ [a²-9a²+9a²]
=-14a²/a²
=-14
我有一道题想请教各位高手:已知a/b=1/3,则a2-2ab-b2/ a2-3ab+b2=( )
我有一道题想请教各位高手:已知a/b=1/3,则a2-2ab-b2/ a2-3ab+b2=( )
数学人气:686 ℃时间:2019-12-05 12:25:29
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