化简3/(sin^220°)-1/(cos^220°)+64sin^220°
化简3/(sin^220°)-1/(cos^220°)+64sin^220°
数学人气：899 ℃时间：2020-04-07 06:54:02
优质解答
3/sin^2 20-1/cos^2 20+64sin20=[3(cos20)^2-(sin20)^2]/(sin20)^2(cos20)^2+64(sin20)^2 =[(√3cos20+sin20)(√3cos20-sin20)]/(sin20cos20)^2+64(sin20)^2 =[2sin(60+20)*2sin(60-20)]/[(sin40)/2]^2+64(sin20)^2 ...
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