已知数列{an}满足an>0,a1=3 根号下[a(n+1)]=(根号下an)+1 （n属于N*) 则an=?

设bn = 根号an
所以
b(n+1) = bn+1
b1 = 根号a1 = 根号3
bn = 根号3 + (n-1)*1 = n+根号3-1
即根号an = n+根号3-1
所以an = [n+根号3-1]^2
楼上那个n=1 就不对了……