log2^3=a,则lg3/lg2=a
lg3=alg2
3^b=7,则log3^7=b
lg7/lg3=b
lg7=blg3=ablg2
log12^56=lg56/lg12
=(lg7+lg8)/(lg3+lg4)
=(lg7+3lg2)/(lg3+2lg2)
=(ablg2+3lg2)/(alg2+2lg2)
=(ab+3)/(a+2)=(ablg2+3lg2)/(alg2+2lg2)=(ab+3)/(a+2) 怎么变哒lg7=blg3=ablg2 lg3=alg2我前面解出来了啊,代入=(lg7+3lg2)/(lg3+2lg2)不就是=(ablg2+3lg2)/(alg2+2lg2)吗?=(ablg2+3lg2)/(alg2+2lg2)=[(ab+3)lg2]/[(a+2)lg2]=(ab+3)/(a+2)【分子分母都有lg2,约去】
log2^3=a,3^b=7,a、b表示log12^56
log2^3=a,3^b=7,a、b表示log12^56
数学人气:196 ℃时间:2020-01-29 07:33:13
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