1
原式=lim(1-sinx/x)/(1+arctanx/x)
=lim(1-sinx/x)/lim(1+arctanx/x)
=1/1=1
如果不知道为啥
lim(1-sinx/x)=1
或者
lim(1+arctanx/x)=1
求x趋近于无穷大时(x-sinx)/(x+arctanx)的极限
求x趋近于无穷大时(x-sinx)/(x+arctanx)的极限
数学人气:161 ℃时间:2019-10-10 06:33:49
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