计算x=? √(50-(x/2)^2+√(10-(x/2)^2=√20
计算x=? √(50-(x/2)^2+√(10-(x/2)^2=√20
式子右边是根号20啊
式子右边是根号20啊
数学人气:495 ℃时间:2020-03-31 06:35:25
优质解答
√(50-(x/2)^2+√(10-(x/2)^2=√20√(50-(x/2)^2=√20-√(10-(x/2)^2两边平方50-(x/2)^2=20-2√[200-20(x/2)^2]+10-(x/2)^2√[200-20(x/2)^2]=-10两边平方200-20(x/2)^2=100(x/2)^2=5带入方程的√45+√5=√20显然不...
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