答:
(x-y)的2N次方-(x-y)的2n+1次方+(y-x)的2n-1次方
=(x-y)^(2n)-(x-y)^(2n+1) - (x-y)^(2n-1)
=[ (x-y) -(x-y)^2-1 ] *(x-y)^(2n-1)
= - [ (x-y)^2-(x-y)+1 ] *(x-y)^(2n-1)
(x-y)的2N次方-(x-y)的2n+1次方+(y-x)的2n-1次方,因式分解
(x-y)的2N次方-(x-y)的2n+1次方+(y-x)的2n-1次方,因式分解
数学人气:160 ℃时间:2019-10-26 10:55:53
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