如图,矩形ABCD中,AB=3cm,AD=6cm,点E为AB边上的任意一点,四边形EFGB也是矩形,且EF=2BE,则S△AFC=_cm2.
如图,矩形ABCD中,AB=3cm,AD=6cm,点E为AB边上的任意一点,四边形EFGB也是矩形,且EF=2BE,则S△AFC=______cm2.
数学人气:414 ℃时间:2019-12-15 13:41:40
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连接BF,过B作BO⊥AC于O,过点F作FM⊥AC于M.Rt△ABC中,AB=3,BC=6,AC=AB2+BC2=35BO=AB×BCAC=655∵EF=BG=2BE=2GF,BC=2AB,∴Rt△BGF和Rt△ABC中BGFG=BCAB=2,∴Rt△BGF∽Rt△ABC,∴∠FBG=∠ACB∴AC∥BF∴FM=O...
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