函数z+z(x,y)由方程F(x+y,x+z)=1所确定,其中F有二阶连续偏导数,且F2不等于0,求∂^2z/∂y^2
函数z+z(x,y)由方程F(x+y,x+z)=1所确定,其中F有二阶连续偏导数,且F2不等于0,求∂^2z/∂y^2
数学人气：911 ℃时间：2020-05-14 11:18:15
优质解答
F(x+y,x+z)=1F1+F2(∂z/∂y)=0 ∂z/∂y= -F1/F2∂²z/∂y²=[-F2(F11+F12(∂z/∂y))+F1(F21+F22(∂z/∂y)]/F2^2=[-F2(F11+F12(-F1/F2))+F1(F21+F22(-F1/...
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