函数z+z(x,y)由方程F(x+y,x+z)=1所确定,其中F有二阶连续偏导数,且F2不等于0,求∂^2z/∂x^2
函数z+z(x,y)由方程F(x+y,x+z)=1所确定,其中F有二阶连续偏导数,且F2不等于0,求∂^2z/∂x^2
数学人气:334 ℃时间:2020-04-24 05:20:53
优质解答
F(x+y,x+z)=1F1+F2(1+∂z/∂x)=0 ∂z/∂x=-F1/F2-1∂^2z/∂x^2=[-F2(F11+F12(1+∂z/∂x))+F1(F21+F22(1+∂z/∂x)]/F2^2
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