a^2+2ab+b^2=0
(a+b)²=0
a+b=0
a(a+4b)-(a+2b)(a-2b)
=a²+4ab-(a²-4b²)
=4ab+4b²
=4b(a+b)
=0
已知a^2+2ab+b^2=0,求代数式a(a+4b)-(a+2b)(a-2b)的值
已知a^2+2ab+b^2=0,求代数式a(a+4b)-(a+2b)(a-2b)的值
其他人气：881 ℃时间：2019-10-09 09:43:55
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