利用公式法解一元二次方程：1.（2x+1）（x+1）=6 2.x²-4x-1=0 3.x²+3x+1=0

1.(2x+1)(x+1)=6 2x²+3x-5=0(x-1)(2x+5)=0x1=1 x2=-5/22.x²-4x-1=0x²-4x+4=5(x-2)²=5x-2=±√5x1=2+√5 x2=2- √53.x²+3x+1=0△=3²-4×1×1=5x1=(-3+√5)/2 x2=(-3-√5)/2