矩阵标准化怎么求啊?

用zscore函数.
>> help zscore
ZSCORE Standardized z score.
Z = ZSCORE(X) returns a centered, scaled version of X, the same size as X.
For vector input X, Z is the vector of z-scores (X-MEAN(X)) ./ STD(X).
标准化的意思就是使平均值等于0,标准差等于1.
例如：
>> A=[0.0371 0.0353 0.0334 0.0353 0.0345 0.0369
0.3905 0.1000 0.3415 0.4249 0.3899 0.3037
0.00095 0.00069 0.00057 0.00061 0.00094 0.00113
0.2277 0.1552 0.1901 0.1502 0.2260 0.1477]
>>B=zscore(A)
>>mu=sum(B)
>>sigma=std(B)
B =
-0.7023 -0.5463 -0.6880 -0.6106 -0.7092 -0.6281
1.25250.39631.27491.41471.25491.3329
-0.9022 -1.0505 -0.8972 -0.7909 -0.8947 -0.8911
0.35201.20040.3103 -0.01330.34910.1863
mu=
1.0e-015 *
0.0555 00.0555 -0.3123 00.1110
sigma=
1.00001.00001.00001.00001.00001.0000