求出函数y=sinX平方+cosX+1在[-π/4,2π/3]的值域!急,求详细过程
求出函数y=sinX平方+cosX+1在[-π/4,2π/3]的值域!急,求详细过程
急!
是sin^x
急!
是sin^x
数学人气:547 ℃时间:2020-03-16 19:53:35
优质解答
令t=cosx,则-1/2=
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