s7=(a1+a7)*7/2=3(a3+a7)
所以7(a1+a1+6d)=6(a1+2d+a1+6d)
所以a1=3d
s9/a4
=[(a1+a9)*9/2]/a4
=(a1+a1+8d)*9/[2(a1+3d)]
=14d*9/12d
=21/2
Sn是等差数列{an}的前n项和,S7=3(a3+a7),那么S9/a4=?
Sn是等差数列{an}的前n项和,S7=3(a3+a7),那么S9/a4=?
数学人气：738 ℃时间：2020-07-01 01:53:56
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