a²+b²=1 则a²=1-b²b²= 1-a²
a×根号下1-b² +b×根号下1-a²
=a*a+b*b
=a²+b²
=1
已知实数a、b满足a²+b²=1,ab＞0,求a×根号下1-b² +b×根号下1-a²的值
已知实数a、b满足a²+b²=1,ab＞0,求a×根号下1-b² +b×根号下1-a²的值
初一数学
快一些
初一数学
快一些
数学人气：256 ℃时间：2019-08-27 11:13:45
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