(sin68°-cos60°sin8°)/(cos68°+sin60°sin8°)
=[sin(60+8)-cos60sin8]/[cos(60+8)+sin60sin8]
=[sin60cos8+sin8cos60-cos60sin8]/[cos60cos8-sin60sin8+sin60sin8]
=sin60cos8/(cos60cos8)
=tan60
=√3
望采纳
化简sin68°-cos60°sin8°/cos68°+sin60°sin8°
化简sin68°-cos60°sin8°/cos68°+sin60°sin8°
数学人气：457 ℃时间：2020-04-16 16:58:43
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