在a-bcd中,bc⊥ad,∠acb=∠bcd=45° ,∠acd=60°,求面abc⊥面bcd

过点A作AE⊥CD,垂足为E,作AF⊥BC,垂足为 F在Rt△ADE中,∠ADC=45°∵AD=2√2∴AE=ED=2∵AC平分∠BCD=60°∴∠ACD=∠ACB=30°,AE=AF=2在Rt△ACE和Rt△ACF中FC=2√3,CE=2√3在Rt△AFB中∵AB=2√2,AF=2∴BF=2则四边形ABC...