(x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9)
(x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9)
数学人气:853 ℃时间:2020-03-21 15:13:44
优质解答
原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-3)²=-[(x-3)+(x+1)]/(x-3)²=-(2x-2)/(x²-6x+9)
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