(x+2/x^2-3x+2)-(2x/x^2-3x+2)-(x+1/x^2-6x+9)

原式=(x+2-2x)/(x²-3x+2)-(x+1)/(x²-6x+9)
=-(x-2)/(x-1)(x-2)-(x+1)/(x-3)²
=-1/(x-1)-(x+1)/(x-3)²
=-[(x-3)²+(x+1)(x-1)]/(x-1)(x-3)²
=-(2x²-6x+8)/(x-1)(x-3)²你再看看，我打错了，我知道答案，不知道步骤(x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9)那是你错了采纳我，重新问你再答一次，我一样给你采纳