log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,

log2[log3(log4x)]=0=log2(1)log3(log4x)=1=log3(3)log4x=3=3log4(4)=log4(4^3)x=4^3=64log3[log4(log2y)]=0=log3(1)log4(log2y)=1=log4(4)log2y=4=4log2(2)=log2(2^4)y=2^4=16x+y=80因为我是今天刚刚学的这部分，老师布置的题中有这一个，说实话我一步也没看懂若loga(b)=loga(c)则b=c
loga(a)=1
loga(1)=0