函数f（x）=根号2 sin（2x+π/4）令g（x）=f（x+π/8）-a,若g（x）在x∈[-π/6,π/3]时有两个零点,

函数f（x）=根号2 sin（2x+π/4）g（x）=f（x+π/8）-a=根号2 sin（2(x+π/8)+π/4）-a=根号2sin(2x+π/2)-a=根号2cos(2x)-ax∈[-π/6,π/3] 2x∈[-π/3,2π/3] 根号2cos(2x) ∈[-√2/2,√2] 由图像可知 g（x）在x∈...