故132=
132−1 |
2 |
132+1 |
2 |
(2)规律为:(2n+1)2=(
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |
(3)(
(2n+1)2+1 |
2 |
(2n+1)2−1 |
2 |
=[(
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |
=(2n+1)2.
即三个数是勾股数.
132−1 |
2 |
132+1 |
2 |
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |
(2n+1)2+1 |
2 |
(2n+1)2−1 |
2 |
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |
(2n+1)2−1 |
2 |
(2n+1)2+1 |
2 |