已知奇函数y=f(x),x属于（-1,1）,在定义域上是减函数,解不等式f(1-x)+f(1-x^2)

函数定义域为(-1,1):
-1 < 1 - x < 1,0 < x < 2 (1)
-1 < 1 - x^2 < 1,-2 < -x^2 < 0,0 < x^2 < 2,0 < x < √2或-√2 < x < 0 (2)
结合(1)(2),0 < x < √2,不等式的解必须在此范围内.(3)
f(x)是奇函数:f*(1 - x) + f(1 - x^2) = f(1 - x) - f(x^2 -1) < 0
f(1-x) < f(x^2 -1)
f(x)是减函数:1 - x > x^2 -1,-x^2 - x +2 > 0,x^2 + x -2 < 0
(x + 2)(x -1) < 0
x < -2 且 x > 1 (无解)
-2 < x < 1 (4)
结合(3)(4),0 < x < 1