已知x^2加根号2y等于根号3,y的平方加根号2x等于根号3,x≠y,求xy,x+y的值

x²+√2y=√3.1y²+√2x=√3.21-2得：x²+√2y-(y²+√2x)=0x²-y²+√2（y-x）=0（x+y）(x-y)-√2（x-y）=0（x-y）（x+y-√2）=0∵x≠y,∴x-y≠0∴x+y-√2=0,x+y=√2又1+2式得：x²+√...