It is given that f(x-1)= -2(x-1)^3 + (x-1)^2 +x-1 and g(x)=2x^3 - x^2 - x +k.If..
It is given that f(x-1)= -2(x-1)^3 + (x-1)^2 +x-1 and g(x)=2x^3 - x^2 - x +k.If..
It is given that f(x-1)= -2(x-1)^3 + (x-1)^2 +x-1 and g(x)=2x^3 - x^2 - x +k.If the graph of y= g(x) is obtained by translating the graph of y=f(x) upwards by 3 units,and then reflecting the resulting graph about the x-axis ,find the value of k.
It is given that f(x-1)= -2(x-1)^3 + (x-1)^2 +x-1 and g(x)=2x^3 - x^2 - x +k.If the graph of y= g(x) is obtained by translating the graph of y=f(x) upwards by 3 units,and then reflecting the resulting graph about the x-axis ,find the value of k.
英语人气：780 ℃时间：2020-05-26 06:35:47
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k=3怎样计数出来的?f(x-1)= -2(x-1)^3 + (x-1)^2 +x-1令y=x-1f(y)=-2y^3+y^2+yf(x)=-2x^3+x^2+x=-g(x)+kg(x)=-f(x)+k=-(f(x)-k)k=-3 向上 相当于f(x)+3 然后x轴对陈 添负号刚算错了。。。
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