令A=1/11+1/13+1/17,
所以原式=(1+A)(A+1/19)-(1+A+1/19)A
=(A^2+20A/19+1/19)-(A^2+20A/19)
=1/19.
所以原式=1/19.采纳不
(1+11/1+13/1+17/1)×(11/1+13/1+17/1+19/1)×(11/1+13/1+17/1)等于多少
(1+11/1+13/1+17/1)×(11/1+13/1+17/1+19/1)×(11/1+13/1+17/1)等于多少
数学人气:774 ℃时间:2019-12-15 14:20:59
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