已知x-y=2分之1+根号3,z-y=2分之1-根号3,求x²+y²+z²-xy-yz-xz的值

x^2+y^2+z^2-xy-yz-xz=(1/2)[(x-y)^2+(z-y)^2+(z-x)^2]x-y=1/2+根号3z-y=1/2-根号3所以y=x-(1/2+根号3)=z-(1/2-根号3)z-x=-2倍根号3带入(1/2)[(x-y)^2+(z-y)^2+(z-x)^2] 得出结果就好啦应该是37/4吧...