计算.（1）5.2-（负3/4）+（+5/6）-（负7/12） （2）+3又8/11的绝对值-10/27的绝对值-9/11的绝对值+

解(1)
原式=26/5+3/4+5/6+7/12
=26/5+9/12+10/12+7/12
=26/5+13/6
=156/30+65/30
=221/30
解(2)
原式=3又8/11-10/27-9/11+9/5
=41/11-10/27-9/11+9/5
=(41/11-9/11)+9/5-10/27
=32/11+9/5-10/27
=4320/1485+2673/1485-550/1485
=4又503/1485我打错了，第二个式子应该是3又8/11-10/27-19/11+9/5你好：3又8/11-10/27-19/11+9/5 =(3又8/11-19/11)-10/27+9/5 =(41/11-19/11)-10/27+9/5 =2-10/27+9/5 =44/27+9/5 =220/135+243/135 =463/135