三角形ABC中,a方+c方-b方=ac,有log4sinA+log4sinC= -1,且三角形ABC的面积S=根号3cm平方,求三边和三角

由 a^2+c^2-b^2=ac 得ac=2ac*sinB
=>sinB=1/2=>B=60度
S=ac*sinB/2=根号3
=>ac=4*根号3
{a/sinA=c/sinC
=>sinC=c*sinA/a
log4sinA+log4sinC= -1
=>log4sinA+log4c*sinA/a=-1
=>a=4c*(sinA)^2}
=>2R=4*4次根号3
b/sinB=2R=>b=4次根号3
a,c条件不足不能求出