证明:
Cn=[(n+1)+3][(n+2)+3]/[(n+1)(n+2)]
=1+3[1/(n+1)+1/(n+2)]+9[1/(n+1)-1/(n+2)]
=1+6[2/(n+1)-1/(n+2)]
0,f(x)上凹,
有f[(x1+x2)/2]
数列与不等式结合证明题.
数列与不等式结合证明题.
Cn=[(n+4)(n+5)]/[(n+1)(n+2)].Sn为数列{Cn}的前n项和,证明Sn
Cn=[(n+4)(n+5)]/[(n+1)(n+2)].Sn为数列{Cn}的前n项和,证明Sn
数学人气:464 ℃时间:2020-05-04 06:40:18
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