顶点在原点,焦点在X轴上的抛物线截直线Y=2X-4所得的弦长AB=3倍更号5,求此抛物线方程

y^2=2px所以(2x-4)^2=2px4x^2-16x+16=2px2x^2-(8+p)x+8=0x1+x2=(8+p)/2,x1x2=4所以(x1-x2)^2=(x1+x2)^2-4x1x2=(p+8)^2/4-16=(p^2+16p)/4(y1-y2)^2=[(2x1-4)-(2x2-4)]^2=[2(x1-x1)]^2=p^2+16p所以AB^2=(x1-x2)^2+(y1-...