已知f(x)=x[1\(-n^2+2n+3)](n属于Z）的图像在[0,正无穷）上单调递增,解不等式f(x^2-x)>f(x+3)

已知f(x)=x[1\(-n^2+2n+3)](n属于Z）的图像在[0,正无穷）上单调递增1\(-n^2+2n+3)>0f(x^2-x)>f(x+3) (x^2-x)[1\(-n^2+2n+3)]>(x+3)[1\(-n^2+2n+3)] x^2-x>x+3x^2-2x-3>0(x-3)(x+1)>0解得x3