将f(x）=cos(x-π/6)+sinx化成标准三角函数

f(x）=cos(x-π/6)+sinx
=cosxcosπ/6+sinxsinπ/6+sinx
=√3/2*cosx+1/2*sinx+sinx
=√3(1/2*cosx+√3/2*sinx)
=√3(sinπ/6*cosx+cosπ/6*sinx)
=√3sin(π/6+x)我刚学，标准化公式也不懂，希望配上文字说明