求函数f(x)=(x-1)^3(x+2)^2的单调区间和极值

f'(x)=3(x-1)^2(x+2)^2+2(x-1)^3(x+2)=(x-1)^2(x+2)[3x+6+2x-2]=(x-1)^2(x+2)(5x+4)由f'(x)=0得x=1,-2,-4/5但在x=1左右邻域,f'(x)不变号,因此它不是极值点；单调增区间：x-4/5单调减区间：(-2,-4/5)极大值f(-2)=0极...