值为相反数则相加为0
所以[1/2(x-3)-2]+[3(x+1)]=0
两边乘2
(x-3)-4+6(x+1)=0
x-3-4+6x+6=0
7x=1
x=1/7
当x是什么数时,代数式1/2(x-3)-2与3(x+1)的值为相反数?
当x是什么数时,代数式1/2(x-3)-2与3(x+1)的值为相反数?
数学人气：648 ℃时间：2019-09-29 06:45:46
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