问一道题；已知x=2008-5称根号3求代数式x的平方-1/x方-2x=1÷【1=x=1/x-3】的值

代数式x的平方-1/x方-2x+1÷【1+x+1/x-3】=(x+1)(x-1)/(x+1)^2 ÷【(x-3+x+1)/x-3】=(x-1)/(x+1) ÷【2(x-1)/(x-3)】=(x-1)/(x+1) *(x-3)/2(x-1)=(x-3)/2(x+1)=(2008-5√3-3)/2(2008-5√3+1)=(2005-5√3)/2(2009-5√...