a1+a2+a3+a4=11,an-3+an-2+an-1+an=67
因为m+n=p+q时,am+an=ap+aq
所以a1+an=a2+a(n-1)=……
观察下标得4(a1+an)=88
sn=n(a1+an)/2=286
n=26
等差数列{an}中,前四项的和为21,后四项的和为67,且Sn=286,则n=多少?
等差数列{an}中,前四项的和为21,后四项的和为67,且Sn=286,则n=多少?
数学人气:282 ℃时间:2020-02-05 14:19:13
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