在三角形ABC中,若sin(A+B)sin(A-B)=sinC的平方,则此三角形的形状是?

sin^2C=sin(A+B)*sin(A-B)sin^2[180-(A+B)]=sin(A+B)*sin(A-B)sin^2(A+B)=sin(A+B)*sin(A-B)sin(A+B)=sin(A-B)sin(A+B)=sinAcosB+cosAsinB(1)sin(A-B)=sinAcosB-cosAsinB(2)(1)=(2)cosAsinB=0cosA=0 (A=90°) 或sinB...