f(x)=ln(x^2+1),
f'(x)=2x/(x²+1)
f'(-1)=-2/(1+1)=-1
设函数f(x)=ln(x^2+1),则f'(-1)=
设函数f(x)=ln(x^2+1),则f'(-1)=
数学人气:965 ℃时间:2020-01-26 03:16:21
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