已知(x+2)的四次方+y-1的绝对值=0,求5xy-【4x²y-(-3xy²+2x²+2x²y)】的值
已知(x+2)的四次方+y-1的绝对值=0,求5xy-【4x²y-(-3xy²+2x²+2x²y)】的值
数学人气:583 ℃时间:2019-08-16 22:37:07
优质解答
(x+2)的四次方+y-1的绝对值=0(x+2)的四次方=0,y-1的绝对值=0x=-2y=15xy-【4x²y-(-3xy²+2x²+2x²y)】=5xy-【4x²y+3xy²+2x²+2x²y】=5xy-【4x²y+2x²y+3xy²...
我来回答
类似推荐