菱形ABCD的周长为16cm,∠DAB与∠ABC的度数之比为1：2,点O为对角线AC与BD的交点,求BD和AC的长

∵ABCD是菱形；∴AD//BC;∴∠DAB+∠ABC=180°；∠DAB:∠ABC=1:2;∴∠DAB=60°；∠ABC=120°；∵ABCD是菱形；∴AB=BC=CD=AD=周长/4=16/4=4;∴△ABD是等边三角形；∴BD=AB=4;∵ABCD是菱形；∴BD⊥AC;∴OA=OC=根号3/2AB...