判断函数f(x)＝ax+1/x+2(a≠1/2)在（-2，+∞）上的单调性，并证明你的结论．

设x1，x2∈（-2，+∞）且x1＜x2∵f(x)＝ax+2a+1−2ax+2＝a+1−2ax+2（2分）∴f（x2）-f（x1）=(a+1−2ax2+2)−(a+1−2ax1+2)=(1−2a)(1x2+2−1x1+2)=(1−2a)•x1−x2(x2+2)(x1+2)（8分）又∵-2＜x1＜x2，∴x1−x2(x2...