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已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a
已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a
（1）求证0《b/a
（1）求证0《b/a
英语人气：216 ℃时间：2019-11-04 08:01:49
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