x∈[2,8] ∴f(x)∈[1,3]
g(x)=(f(x)-a)^2+3-a^2
当a≥3时 h(a)=g(3)=12-6a
当a≤1时 h(a)=g(1)=4-2a
当1
已知函数f(x)=log2(x),x属于〔2,8〕,函数g(x)=f(x)^2-2af(x)+3的最小值为h(a) (1)求h(a)
已知函数f(x)=log2(x),x属于〔2,8〕,函数g(x)=f(x)^2-2af(x)+3的最小值为h(a) (1)求h(a)
数学人气:386 ℃时间:2019-08-22 10:19:39
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