9 - x² ≥ 0
-3 ≤ x ≤ 3
sinx > 0
x ∈ (2kπ,π + 2kπ),k ∈ Z
所以定义域为{x | 0 < x ≤ 3}
函数y=√9-x²﹙都根号下﹚+1/√sinx的定义域是__?
函数y=√9-x²﹙都根号下﹚+1/√sinx的定义域是__?
数学人气:197 ℃时间:2020-01-28 18:35:21
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